Problem 1:
An arrow is formed in a 2 2 square by joining the bottom corners to the midpoint of the top edge and the centre of the square.
Find the area of the arrow.
Problem 2:Two ladders are placed on opposite diagonals in an alley such that one ladder reaches a units up one wall, the other ladder reaches b units up the opposite wall and they intersect h units above the ground.
Prove the following result.
1 a | + | 1 b | = | 1 h |
Problem 3:
How many digits does the number 21000 contain?
Solution to 1:
Consider the two diagrams below.
The area of the square is 4, so the area of the large triangle is 2 (half of the square) and the area of the small triangle is 1 (quarter of the square).
Hence the area of the arrow is 2 1 = 1 square unit.
Solution to 2:Consider the following diagram:
By similar triangles:
x + y
a= y
hand x + y
b= x
h
Adding equations:
x + y
a+ x + y
b= x + y
h
Dividing by (x + y):
1 a | + | 1 b | = | 1 h |
Solution to 3:
As 21000 is not a multiple of 10, it follows that,
10m 21000 10m + 1, where 10m contains m + 1 digits.
Solving 21000 = 10k, where m k m + 1
k = log 21000 = 1000 log 2 301.02999... , so m = [1000 log 2] = 301.
Hence 21000 contains 302 digits.
The problems and solutions are all taken from http://www.mathschallenge.net
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